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Chemical Equations Balanced on 12/30/18

 Equations balanced on the previous day Equations balanced on the next day
Balance equation of any chemical reaction online for free
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C3H + O2 = CO2 + H2O =>
4 C3H + 13 O2 = 12 CO2 + 2 H2O

H2 + Br = HBr =>
H2 + 2 Br = 2 HBr

H2 + Br = HBr2 =>
H2 + 4 Br = 2 HBr2

CaCO3 = CaO + CO2 =>
CaCO3 = CaO + CO2

H2 + Br2 = HBr =>
H2 + Br2 = 2 HBr

NH3 + O2 = N2 + H2O =>
4 NH3 + 3 O2 = 2 N2 + 6 H2O

NO3{-} + I{-} + H{+} = NO + I2 + H2O =>
2 NO3{-} + 6 I{-} + 8 H{+} = 2 NO + 3 I2 + 4 H2O

KOH + H3PO4 = K3PO4 + H2O =>
3 KOH + H3PO4 = K3PO4 + 3 H2O

NH3 + H2SO4 = (NH4)2SO4 =>
2 NH3 + H2SO4 = (NH4)2SO4

Al + HCl = AlCl + H =>
Al + HCl = AlCl + H

MnO4{-} + S{2-} + H{+} = Mn2{+} + S0 + H2O =>
4 MnO4{-} + 13 S{2-} + 32 H{+} = 2 Mn2{+} + 13 S0 + 16 H2O

KMnO4 + HCl = KCl + MnCl2 + H2O + Cl2 =>
2 KMnO4 + 16 HCl = 2 KCl + 2 MnCl2 + 8 H2O + 5 Cl2

MnO4{-} + S{2-} + H{+} = Mn2{+} + S + H2O =>
4 MnO4{-} + 13 S{2-} + 32 H{+} = 2 Mn2{+} + 13 S + 16 H2O

MnO4{-} + S{2-} + H{+} = Mn{2+} + S + H2O =>
2 MnO4{-} + 5 S{2-} + 16 H{+} = 2 Mn{2+} + 5 S + 8 H2O

Al + HNO3 = Al(NO3)3 + NH4NO3 + H2O =>
8 Al + 30 HNO3 = 8 Al(NO3)3 + 3 NH4NO3 + 9 H2O

Cl2 + KBr = KCl + Br2 =>
Cl2 + 2 KBr = 2 KCl + Br2

Cr2O72{-} + I{-} + H{+} = Cr3{+} + I2 + H2O =>
6 Cr2O72{-} + 854 I{-} + 864 H{+} = 4 Cr3{+} + 427 I2 + 432 H2O

CH4 + Cl2 = CCl4 + HCl =>
CH4 + 4 Cl2 = CCl4 + 4 HCl

CH3COOH + CaSO4 = H2SO4 + Ca(CH3COO)2 =>
2 CH3COOH + CaSO4 = H2SO4 + Ca(CH3COO)2

Cl2 + KI = KCl + I2 =>
Cl2 + 2 KI = 2 KCl + I2

NaAlO2 + HF + NaOH = Na3AlF6 + H2O =>
NaAlO2 + 6 HF + 2 NaOH = Na3AlF6 + 4 H2O

CaCO3(s) + HCl(aq) = H2O(l) + CO2(g) + CaCl2(aq) =>
CaCO3(s) + 2 HCl(aq) = H2O(l) + CO2(g) + CaCl2(aq)

CaCO3(s) + HCl(aq) = H2O(l) + CO2(g) + CaCl2(aq) =>
CaCO3(s) + 2 HCl(aq) = H2O(l) + CO2(g) + CaCl2(aq)

Al4C3 + H2O = Al(OH)3 + CH4 =>
Al4C3 + 12 H2O = 4 Al(OH)3 + 3 CH4

I2O5 + CO = I2 + CO2 =>
I2O5 + 5 CO = I2 + 5 CO2

AsO3{3-} + BrO3{-} = AsO4{3-} + Br{-} =>
3 AsO3{3-} + BrO3{-} = 3 AsO4{3-} + Br{-}

(Cr2O7)2{-} + I{-} + H{+} = Cr3{+} + I2 + H2O =>
6(Cr2O7)2{-} + 154 I{-} + 168 H{+} = 8 Cr3{+} + 77 I2 + 84 H2O

Na2S = Na + S =>
Na2S = 2 Na + S

Na + H2O = NaOH + H2 =>
2 Na + 2 H2O = 2 NaOH + H2

H2SO4 + Ag = Ag2SO4 + SO2 + H2O =>
2 H2SO4 + 2 Ag = Ag2SO4 + SO2 + 2 H2O

Cr{3+} + S2O8{2-} + H2O = CrO7{2-} + SO4{2-} + H{+} =>
2 Cr{3+} + 9 S2O8{2-} + 14 H2O = 2 CrO7{2-} + 18 SO4{2-} + 28 H{+}

(NH4)2CO3 = (NH4){+} + (CO3){2-} =>
(NH4)2CO3 = 2(NH4){+} + (CO3){2-}

CH3COOH + CaSO4 = SO3 + H2O + Ca(CH3COO)2 =>
2 CH3COOH + CaSO4 = SO3 + H2O + Ca(CH3COO)2

CH3CH3 + O2 = CO2 + H2O =>
2 CH3CH3 + 7 O2 = 4 CO2 + 6 H2O

Pb(NO3)2 + KI = KNO3 + PbI2 =>
Pb(NO3)2 + 2 KI = 2 KNO3 + PbI2

(NH4)2Co3 + O2 = NH3 + H2O + Co2 =>
2(NH4)2Co3 + O2 = 4 NH3 + 2 H2O + 3 Co2

Au{3+} + Sn{2+} + H2O = Au + SnO2 + H{+} =>
2 Au{3+} + 3 Sn{2+} + 6 H2O = 2 Au + 3 SnO2 + 12 H{+}

(NH4)2CO3 = NH3 + H2O + CO2 =>
(NH4)2CO3 = 2 NH3 + H2O + CO2

ClO4{-} + Ti{3+} + H{+} = Cl{-} + Ti{4+} + H2O =>
ClO4{-} + 8 Ti{3+} + 8 H{+} = Cl{-} + 8 Ti{4+} + 4 H2O

Cl2 + Ba(OH)2 = Ba(ClO3)2 + BaCl2 + H2O =>
6 Cl2 + 6 Ba(OH)2 = Ba(ClO3)2 + 5 BaCl2 + 6 H2O

NO3{-} + Mg + H{+} = Mg{2+} + NO2 + H2O =>
2 NO3{-} + Mg + 4 H{+} = Mg{2+} + 2 NO2 + 2 H2O

Ca(OH)2(aq) + H3PO4(aq) = H2O(l) + Ca3(PO4)2(s) =>
3 Ca(OH)2(aq) + 2 H3PO4(aq) = 6 H2O(l) + Ca3(PO4)2(s)

Al2O3 + NaOH + HF = Na3AlF6 + H2O =>
Al2O3 + 6 NaOH + 12 HF = 2 Na3AlF6 + 9 H2O

P2 + O2 = P4O10 =>
2 P2 + 5 O2 = P4O10

C4H10 + O2 = CO2 + H2O =>
2 C4H10 + 13 O2 = 8 CO2 + 10 H2O

P + O2 = P4O10 =>
4 P + 5 O2 = P4O10

H2S + SbCl3 = HCl + Sb2S3 =>
3 H2S + 2 SbCl3 = 6 HCl + Sb2S3

Fe + O2 = Fe3O4 =>
3 Fe + 2 O2 = Fe3O4

SeO3{2-} + SO3{2-} + H{+} = Se + SO4{2{-}]} + H2O =>
3 SeO3{2-} + 2 SO3{2-} + 14 H{+} = 3 Se + 2 SO4{2{-}]} + 7 H2O

KMnO4 + NaOH = NaMnO4 + KOH =>
KMnO4 + NaOH = NaMnO4 + KOH

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Balance equation of any chemical reaction online for free
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Equations balanced on 12/23/18
Equations balanced on 11/30/18
Equations balanced on 12/30/17
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