Equations balanced on the previous day | Equations balanced on the next day |
8 H{+} + 3 CuS + 2 NO3{-} = 3 Cu{2+} + 2 NO + 3 S + 4 H2O
CH3CONH2 + H2SO4 + H2O = CH3COOH + NH5SO4 =>
CH3CONH2 + H2SO4 + H2O = CH3COOH + NH5SO4
Al2O3 + Na2SO4 + H2O = Al2(SO4)3 + NaOH =>
Al2O3 + 3 Na2SO4 + 3 H2O = Al2(SO4)3 + 6 NaOH
Al2O3 + BaCl2 = AlCl3 + BaO =>
Al2O3 + 3 BaCl2 = 2 AlCl3 + 3 BaO
Cu(NO3)2(aq) + NaOH(aq) = NaNO3(aq) + Cu(OH)2(aq) =>
Cu(NO3)2(aq) + 2 NaOH(aq) = 2 NaNO3(aq) + Cu(OH)2(aq)
Pb + (NO3)2 + KI = KNO3 + PbI =>
2 Pb + (NO3)2 + 2 KI = 2 KNO3 + 2 PbI
MgCl2 + NH4OH + (NH4)2HPO4 = Mg(NH4)PO4 + NH4Cl + H2O =>
MgCl2 + NH4OH + (NH4)2HPO4 = Mg(NH4)PO4 + 2 NH4Cl + H2O
Mg(NO3)2 + (NH4)2CO3 = MgCO3 + (NO3)2(NH4)2 =>
Mg(NO3)2 + (NH4)2CO3 = MgCO3 + (NO3)2(NH4)2
CuCl2 + MgSO4 = Cu(SO4) + MgCl2 =>
CuCl2 + MgSO4 = Cu(SO4) + MgCl2
Cu{2+} + S2O3{2-} = Cu{+} + S4O6 =>
4 Cu{2+} + 2 S2O3{2-} = 4 Cu{+} + S4O6
HCl + NaAlO2 = NaCl + AlCl3 + H2O =>
4 HCl + NaAlO2 = NaCl + AlCl3 + 2 H2O
Cr(OH)3 + H2O2 + KOH = K2Cr2O7 + H2O =>
2 Cr(OH)3 + 3 H2O2 + 2 KOH = K2Cr2O7 + 7 H2O
CaCl2 + KOH = CaOHCl + KCl =>
CaCl2 + KOH = CaOHCl + KCl
C3H7OH + KMnO4 + HCl = C3H6O + MnCl2 + H2O + KCl =>
5 C3H7OH + 2 KMnO4 + 6 HCl = 5 C3H6O + 2 MnCl2 + 8 H2O + 2 KCl
C2H6 + Cl2 = C2H5Cl2 + H2 =>
2 C2H6 + 2 Cl2 = 2 C2H5Cl2 + H2
CaCO3 + C6H8O7 = Ca + C6H7O7 + H2CO3 =>
CaCO3 + 2 C6H8O7 = Ca + 2 C6H7O7 + H2CO3
H3BO3 + C6H14O6 = H3BO3*C6H14O6 = H3BO3*C6H14O6 + NaOH = Na*H3BO3*C6H14O6 + H2O =>
H3BO3 + C6H14O6 = H3BO3*C6H14O6
MnO4{-} + SO3{2-} + H2O = MnO2 + H2SO4 + OH{-} =>
2 MnO4{-} + 3 SO3{2-} + 7 H2O = 2 MnO2 + 3 H2SO4 + 8 OH{-}
C15H31COOH + NaOH = C15H31COONa + H2O =>
C15H31COOH + NaOH = C15H31COONa + H2O
Zn + Al(OH)3 = Zn(OH)2 + Al =>
3 Zn + 2 Al(OH)3 = 3 Zn(OH)2 + 2 Al
C12H22O11 + Ca(OH)2 = C6H10CaO6 + OH2 =>
C12H22O11 + 2 Ca(OH)2 = 2 C6H10CaO6 + 3 OH2
C8H5KOH(aq) + O2 = CO2 + KOH + H2O(l) =>
4 C8H5KOH(aq) + 37 O2 = 32 CO2 + 4 KOH + 10 H2O(l)
Hg2Cl2 + NH3 = Hg + Cl(NH3) =>
Hg2Cl2 + 2 NH3 = 2 Hg + 2 Cl(NH3)
Na2HPO4 + SOCl2 = Na4P2O7 + SO2 + HCl =>
2 Na2HPO4 + SOCl2 = Na4P2O7 + SO2 + 2 HCl
C8H10 + NO = CO2 + H2O + N =>
C8H10 + 21 NO = 8 CO2 + 5 H2O + 21 N
MgI2 + H2SO4 + NaNO2 = NO + MgSO4 + H2O + I2 + Na2SO4 =>
MgI2 + 2 H2SO4 + 2 NaNO2 = 2 NO + MgSO4 + 2 H2O + I2 + Na2SO4
C3H7OH + K2CrO4 + HCl = C2H5COH + CrCl3 + H2O + KCl =>
3 C3H7OH + 2 K2CrO4 + 10 HCl = 3 C2H5COH + 2 CrCl3 + 8 H2O + 4 KCl
FeO + HNO3 = N2O + Fe(NO3)3 + H2O =>
8 FeO + 26 HNO3 = N2O + 8 Fe(NO3)3 + 13 H2O
Co(OH)3 + HClO2 = Co(ClO2)3 + H2O =>
Co(OH)3 + 3 HClO2 = Co(ClO2)3 + 3 H2O
Na2S + FeSO4 = Fe2O3 + Na2SO4 + SO2 =>
Na2S + 8 FeSO4 = 4 Fe2O3 + Na2SO4 + 8 SO2
fluorine + sulfur = SF6 =>
3 F2 + S = SF6
Cu2NO3 + K = Cu + KNO3 =>
Cu2NO3 + K = 2 Cu + KNO3
XMnO4 + XOX = X2MnO4 + O2 =>
4 XMnO4 + 2 XOX = 4 X2MnO4 + O2
Fe2O3 + C6H8O6 = FeO + C6H6O6 + H2O =>
Fe2O3 + C6H8O6 = 2 FeO + C6H6O6 + H2O
AuS3 + H2 = Au + H2S =>
AuS3 + 3 H2 = Au + 3 H2S
HBr + H2SO4 = Br2 + H2O + SO =>
4 HBr + H2SO4 = 2 Br2 + 3 H2O + SO
CoCl2 + K2S2O8 + KOH = Co(OH)3 + K2SO4 + KCl =>
2 CoCl2 + K2S2O8 + 6 KOH = 2 Co(OH)3 + 2 K2SO4 + 4 KCl
KMnO4 + KBr + H2SO4 = Br2 + K2SO4 + MnS04 + H2O =>
2 KMnO4 + 62 KBr + 40 H2SO4 = 31 Br2 + 32 K2SO4 + 2 MnS04 + 40 H2O
Na2HPO4 + SOCl2 = Na4P2O7 + SO2 + HCl =>
2 Na2HPO4 + SOCl2 = Na4P2O7 + SO2 + 2 HCl
H2SO4(aq) + NaOH(aq) = H2O + Na2SO4(s) =>
H2SO4(aq) + 2 NaOH(aq) = 2 H2O + Na2SO4(s)
H2SO4(aq)K2CO3(aq) = H2CO3K2SO4 =>
H2SO4(aq)K2CO3(aq) = H2CO3K2SO4
(NH4)2SO4 + CuBr2 = CuSO4 + NH4Br =>
(NH4)2SO4 + CuBr2 = CuSO4 + 2 NH4Br
CaCO3 + Na4P2O7 = Ca2P2O7 + Na2CO3 =>
2 CaCO3 + Na4P2O7 = Ca2P2O7 + 2 Na2CO3
H2SO4 + H2I = H2S + I2 + H2O =>
H2SO4 + 4 H2I = H2S + 2 I2 + 4 H2O
Fe + KMnO4 + HCl = FeCl2 + MnCl2 + KCl + H2O =>
5 Fe + 2 KMnO4 + 16 HCl = 5 FeCl2 + 2 MnCl2 + 2 KCl + 8 H2O
Mg(NO3)2 + (NH4)2CO3 = MgCO3 + (NO3)2(NH4)2 =>
Mg(NO3)2 + (NH4)2CO3 = MgCO3 + (NO3)2(NH4)2
ArBr = Ar + Br =>
ArBr = Ar + Br
Na2B4O7*10H2O(borax) + HCl = NaCl + H3BO3 + H2O =>
Na2B4O7*10H2O(borax) + 2 HCl = 2 NaCl + 4 H3BO3 + 5 H2O
Na2S + FeSO4 = Fe2O3 + Na2SO4 + SO2 =>
Na2S + 8 FeSO4 = 4 Fe2O3 + Na2SO4 + 8 SO2
NaHCO3 + HBr = NaBr + HHCO3 =>
NaHCO3 + HBr = NaBr + HHCO3
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 11/25/23
Equations balanced on 12/25/22
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