Equations balanced on the previous day | Equations balanced on the next day |
Bi + H2S = BiS + 2 H
C2H5OH + O2 = CO2 + H2O =>
C2H5OH + 3 O2 = 2 CO2 + 3 H2O
FeO2 + H2O = FeO3 + H =>
FeO2 + H2O = FeO3 + 2 H
AgCl + NH4OH = [Ag(NH3)2]Cl + H2O =>
AgCl + 2 NH4OH = [Ag(NH3)2]Cl + 2 H2O
CsOH + NaCl = CsCl + NaOH =>
CsOH + NaCl = CsCl + NaOH
NH2CH2CONHCH2(CH3)COOH + HCl + H2O = NH2CH2COOH + NH3ClCH2(CH3)COOH =>
NH2CH2CONHCH2(CH3)COOH + HCl + H2O = NH2CH2COOH + NH3ClCH2(CH3)COOH
C2H3O2 + CH3CH2OH = CH3COOCH2CH3 + H2O =>
4 C2H3O2 + 6 CH3CH2OH = 5 CH3COOCH2CH3 + 4 H2O
KMnO4 + H2SO4 + Fe = Fe2(SO4)3 + MnSO4 + K2SO4 + H2O =>
6 KMnO4 + 24 H2SO4 + 10 Fe = 5 Fe2(SO4)3 + 6 MnSO4 + 3 K2SO4 + 24 H2O
Zn + H2SO4 = ZnSO4 + H2O + H2S =>
4 Zn + 5 H2SO4 = 4 ZnSO4 + 4 H2O + H2S
K2[Zn(OH)4] + HBr = Zn(OH)2 + KBr + H2O =>
K2[Zn(OH)4] + 2 HBr = Zn(OH)2 + 2 KBr + 2 H2O
XCHO + NaBH4 + NaOH + H2O = XCH2OH + Na3BO3 =>
4 XCHO + NaBH4 + 2 NaOH + H2O = 4 XCH2OH + Na3BO3
CH3OH + H2 = CH4 + H2O =>
CH3OH + H2 = CH4 + H2O
O2 + (CH2OH)2 = H2O + CO2 =>
5 O2 + 2(CH2OH)2 = 6 H2O + 4 CO2
Pb + H2SO4 + KI = PbI2 + K2SO4 + H2 =>
Pb + H2SO4 + 2 KI = PbI2 + K2SO4 + H2
CH4 + Cl2 = CH3Cl2 + HCl =>
2 CH4 + 3 Cl2 = 2 CH3Cl2 + 2 HCl
C3H7OH + O2 = CO2 + H2O =>
2 C3H7OH + 9 O2 = 6 CO2 + 8 H2O
Pb(OH)2 + HNO2 = Pb(OH)NO2 + H2O =>
Pb(OH)2 + HNO2 = Pb(OH)NO2 + H2O
C3H8 + O2 = CO2 + H2O =>
C3H8 + 5 O2 = 3 CO2 + 4 H2O
CuCl + NaClO3 + HCl = CuCl2 + NaCl + H2O =>
6 CuCl + NaClO3 + 6 HCl = 6 CuCl2 + NaCl + 3 H2O
CH3CCCH3 + KMnO4 + H2SO4 = CH3COOH + MnSO4 + K2SO4 + H2O =>
5 CH3CCCH3 + 6 KMnO4 + 9 H2SO4 = 10 CH3COOH + 6 MnSO4 + 3 K2SO4 + 4 H2O
NaCl + FeCl3 = NaFe + Cl =>
NaCl + FeCl3 = NaFe + 4 Cl
HCl(aq) + FeCl2(aq) + KMnO4(aq) = FeCl3(aq) + H2O(l) + KCl + MnCl2 =>
8 HCl(aq) + 5 FeCl2(aq) + KMnO4(aq) = 5 FeCl3(aq) + 4 H2O(l) + KCl + MnCl2
CuS(s) + O2(g) = Cu2O(s) + SO2(g) =>
4 CuS(s) + 5 O2(g) = 2 Cu2O(s) + 4 SO2(g)
Al + NH4ClO4 = Al2O3 + AlCl + N2 + H2O =>
14 Al + 6 NH4ClO4 = 4 Al2O3 + 6 AlCl + 3 N2 + 12 H2O
Sb + S = Sb2S5 =>
2 Sb + 5 S = Sb2S5
Al2Cl3 + NH4OH = (NH4)2Cl + Al(OH)3 =>
Al2Cl3 + 6 NH4OH = 3(NH4)2Cl + 2 Al(OH)3
Na3PO4 + Cu(OH)2 = NaOH + Cu3(PO4)2 =>
2 Na3PO4 + 3 Cu(OH)2 = 6 NaOH + Cu3(PO4)2
Na2S(aq) + Mg(NO3)2(aq) = MgS(aq) + Na(NO3)(aq) =>
Na2S(aq) + Mg(NO3)2(aq) = MgS(aq) + 2 Na(NO3)(aq)
Ca3(PO4)2 + H2SO4 = CaSO4 + Ca(H2PO4)2 =>
Ca3(PO4)2 + 2 H2SO4 = 2 CaSO4 + Ca(H2PO4)2
C2H5 + KMnO4 = H2O + KCH3COO + MnO =>
C2H5 + KMnO4 = H2O + KCH3COO + MnO
K2Cr2O3 + H2SO4 + O2 = Cr2(SO4)3 + K(HSO4) + H2O =>
2 K2Cr2O3 + 10 H2SO4 + O2 = 2 Cr2(SO4)3 + 4 K(HSO4) + 8 H2O
AgOH + NaCl = AgCl + NaOH =>
AgOH + NaCl = AgCl + NaOH
Au(s) + HCl(aq) = AuCl2(aq) + H2(g) =>
Au(s) + 2 HCl(aq) = AuCl2(aq) + H2(g)
Na2O + Cl2 = O2 + NaCl =>
2 Na2O + 2 Cl2 = O2 + 4 NaCl
PbCO3 = PbO + CO2 =>
PbCO3 = PbO + CO2
C3H8 + O2 = CO2 + H2O =>
C3H8 + 5 O2 = 3 CO2 + 4 H2O
C2H2 + KMnO4 + H2O = HCO2H + KOH + MnO2 =>
C2H2 + 2 KMnO4 + 2 H2O = 2 HCO2H + 2 KOH + 2 MnO2
NH3 + N2O = N2H4 + O2 =>
8 NH3 + 2 N2O = 6 N2H4 + O2
NaNO2 + H2O2 + H2SO4 = HNO3 + Na2SO4 + H2O =>
2 NaNO2 + 2 H2O2 + H2SO4 = 2 HNO3 + Na2SO4 + 2 H2O
KIO3 + NaHSO3 + H2SO4 = I2 + NaHSO4 + K2SO4 + H2O =>
2 KIO3 + 5 NaHSO3 + H2SO4 = I2 + 5 NaHSO4 + K2SO4 + H2O
NF3(g) + H2O(g) = HF(g) + NO(g) + NO2(g) =>
2 NF3(g) + 3 H2O(g) = 6 HF(g) + NO(g) + NO2(g)
CrCl2 + H2O = CrH2OCl2 =>
CrCl2 + H2O = CrH2OCl2
C5H12 + O2 = CO2 + H2O = = = = = = = =>
C5H12 + 8 O2 = 5 CO2 + 6 H2O
C6H6 + O2 = CO2 + H2O =>
2 C6H6 + 15 O2 = 12 CO2 + 6 H2O
MnSO4 + KHCO3 = Mn(HCO3)2 + K2SO4 =>
MnSO4 + 2 KHCO3 = Mn(HCO3)2 + K2SO4
CH3COOHOH = CH4COOHO =>
CH3COOHOH = CH4COOHO
Cr + HCl + H2O = CrCl(H2O)5 + H2 =>
2 Cr + 2 HCl + 10 H2O = 2 CrCl(H2O)5 + H2
Fe(NO3)3*9H2O + NH3 = Fe(OH)3 + NH4NO3 + H2O =>
Fe(NO3)3*9H2O + 3 NH3 = Fe(OH)3 + 3 NH4NO3 + 6 H2O
K2CrO7 + H2S + HCl = KCl + CrCl3 + S + H2O =>
2 K2CrO7 + 9 H2S + 10 HCl = 4 KCl + 2 CrCl3 + 9 S + 14 H2O
F2 + AlCl3 = AlF3 + Cl2 =>
3 F2 + 2 AlCl3 = 2 AlF3 + 3 Cl2
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 12/18/23
Equations balanced on 01/17/23
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