Equations balanced on the previous day | Equations balanced on the next day |
2 Ce(SO4)2 + H2O2 = Ce2(SO4)3 + O2(g) + H2SO4
C14H28O4 + O2 = H2O + CO2 =>
C14H28O4 + 19 O2 = 14 H2O + 14 CO2
NH4Cl(g) + KOH(s) = NH3(g) + H2O(g) + KCl =>
NH4Cl(g) + KOH(s) = NH3(g) + H2O(g) + KCl
Sb2O5 = Sb + O =>
Sb2O5 = 2 Sb + 5 O
N2H4 + KReO4 + H2SO4 = N2 + K2SO4 + ReSO4 + H2O =>
5 N2H4 + 4 KReO4 + 6 H2SO4 = 5 N2 + 2 K2SO4 + 4 ReSO4 + 16 H2O
I2 + H2O = HOI + HI =>
I2 + H2O = HOI + HI
FeS2 + HNO3 = Fe2(SO4)3 + H2O + H2SO4 + NO =>
2 FeS2 + 10 HNO3 = Fe2(SO4)3 + 4 H2O + H2SO4 + 10 NO
Zn(OH)2 + C10H12O2 = Zn(C10H11O2)2 + H2O =>
Zn(OH)2 + 2 C10H12O2 = Zn(C10H11O2)2 + 2 H2O
Al(NO3)3 + PF = P(NO3) + AlF3 =>
Al(NO3)3 + 3 PF = 3 P(NO3) + AlF3
NH4 + KOH = KOHNH4 =>
NH4 + KOH = KOHNH4
FeS2 + HNO3 = Fe2(SO4)3 + H2O + H2SO4 + NO =>
2 FeS2 + 10 HNO3 = Fe2(SO4)3 + 4 H2O + H2SO4 + 10 NO
Sb2O5 = Sb2O4 + O2 =>
2 Sb2O5 = 2 Sb2O4 + O2
NH4Cl(g) + KOH(s) = NH3(g) + H2O(g) + KCl =>
NH4Cl(g) + KOH(s) = NH3(g) + H2O(g) + KCl
Pb2S + O2 = Pb2O + SO2 =>
2 Pb2S + 3 O2 = 2 Pb2O + 2 SO2
Cs + HNO3 = Cs3NO3 + H2 =>
6 Cs + 2 HNO3 = 2 Cs3NO3 + H2
NaNO3 + S + CaCO3 = NaNO2 + CaSO4 + CO2 =>
3 NaNO3 + S + CaCO3 = 3 NaNO2 + CaSO4 + CO2
(NH4)2Cr2O7 + O2 = CrO3 + H2O + N2 =>
2(NH4)2Cr2O7 + 3 O2 = 4 CrO3 + 8 H2O + 2 N2
NH4Cl(g) + KOH(s) = NH3(g) + H2O(g) + KCl =>
NH4Cl(g) + KOH(s) = NH3(g) + H2O(g) + KCl
NaC17H33COO + ZnSO4 = (C17H33COO)2Zn + Na2SO4 =>
2 NaC17H33COO + ZnSO4 = (C17H33COO)2Zn + Na2SO4
FeS2 + HNO3 = Fe2(SO4)3 + H2O + H2SO4 + NO =>
2 FeS2 + 10 HNO3 = Fe2(SO4)3 + 4 H2O + H2SO4 + 10 NO
I2 + H2O = HI + O2 =>
2 I2 + 2 H2O = 4 HI + O2
Si + NaOH = NaSiO + H2 =>
2 Si + 2 NaOH = 2 NaSiO + H2
I2 + H2O = HI + HIO3 =>
3 I2 + 3 H2O = 5 HI + HIO3
Sb2O5 = SbO{+} + {-} + O2 =>
2 Sb2O5 = 4 SbO{+} + 4e + 3 O2
NH4Cl(g) + KOH(s) = NH3(g) + H2O(g) + KCl =>
NH4Cl(g) + KOH(s) = NH3(g) + H2O(g) + KCl
NaC17H33COO + ZnSO4 = (C17H33COO)2Zn + Na2SO4 =>
2 NaC17H33COO + ZnSO4 = (C17H33COO)2Zn + Na2SO4
Zn2 + K + Fe(CN)6 = Zn3K2[Fe(CN)6]2 =>
3 Zn2 + 4 K + 4 Fe(CN)6 = 2 Zn3K2[Fe(CN)6]2
I2 + H2O = HIO3 + H =>
I2 + 6 H2O = 2 HIO3 + 10 H
SO2 + H2 = SOH + H2O =>
2 SO2 + 3 H2 = 2 SOH + 2 H2O
FeS2 + HNO3 = Fe2(SO4)3 + H2O + H2SO4 + NO =>
2 FeS2 + 10 HNO3 = Fe2(SO4)3 + 4 H2O + H2SO4 + 10 NO
CoSO4 + NaOH = CoOH + NaSO4 =>
CoSO4 + NaOH = CoOH + NaSO4
NaC17H33COO + ZnSO4 = (C17H33COO)2Zn + Na2SO4 =>
2 NaC17H33COO + ZnSO4 = (C17H33COO)2Zn + Na2SO4
NH4Cl(g) + KOH(s) = NH3(g) + H2O(g) + KCl =>
NH4Cl(g) + KOH(s) = NH3(g) + H2O(g) + KCl
AgNO3(aw) + NaCl(aq) = AgCl(aq) + NaNO3 =>
AgNO3(aw) + NaCl(aq) = AgCl(aq) + NaNO3
HF = H2 + F2 =>
2 HF = H2 + F2
FeBr3 + OH = FeBr3OH =>
FeBr3 + OH = FeBr3OH
NaHCO3*H2O + HCl = NaCl + H2O + CO2 =>
NaHCO3*H2O + HCl = NaCl + 2 H2O + CO2
(NH4)2Cr2O7 + O2 = Cr2O3 + N2O5 + H2O =>
2(NH4)2Cr2O7 + 5 O2 = 2 Cr2O3 + 2 N2O5 + 8 H2O
Cu(NO3)2 + H2O = Cu(NO3)2H2O =>
Cu(NO3)2 + H2O = Cu(NO3)2H2O
(NH4)2Cr2O7 + O2 = CrO3 + H2O + N2 =>
2(NH4)2Cr2O7 + 3 O2 = 4 CrO3 + 8 H2O + 2 N2
KMnO4 + Na + H2O = MnO2 + NaOH + KOH =>
KMnO4 + 3 Na + 2 H2O = MnO2 + 3 NaOH + KOH
FeS2 + HNO3 = Fe2(SO4)3 + H2O + H2SO4 + NO =>
2 FeS2 + 10 HNO3 = Fe2(SO4)3 + 4 H2O + H2SO4 + 10 NO
NaC17H33COO + ZnSO4 = (C17H33COO)2Zn + Na2SO4 =>
2 NaC17H33COO + ZnSO4 = (C17H33COO)2Zn + Na2SO4
FeCl3 + H2O2 = O2 + FeCl + HCl =>
FeCl3 + H2O2 = O2 + FeCl + 2 HCl
NH4Cl(g) + KOH(s) = NH3(g) + H2O(g) + KCl(s) =>
NH4Cl(g) + KOH(s) = NH3(g) + H2O(g) + KCl(s)
Sb2O5 = SbO{+} + {-} + O2 =>
2 Sb2O5 = 4 SbO{+} + 4e + 3 O2
NH4Cl(g) + KOH(s) = NH3(g) + H2O(g) + KCl(g) =>
NH4Cl(g) + KOH(s) = NH3(g) + H2O(g) + KCl(g)
HF = H + F =>
HF = H + F
MnO2 + CoCl2 + HCl = CoCl3 + MnCl2 + H2O =>
MnO2 + 2 CoCl2 + 4 HCl = 2 CoCl3 + MnCl2 + 2 H2O
Sn(NO3)2 + KOH = Sn(OH)2 + KNO3 =>
Sn(NO3)2 + 2 KOH = Sn(OH)2 + 2 KNO3
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 12/28/23
Equations balanced on 01/27/23
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