Equations balanced on the previous day | Equations balanced on the next day |
MnCO3 = MnO + CO2
Mg + O2 = MgO =>
2 Mg + O2 = 2 MgO
CaHPO4 + H3PO4 = Ca(H2PO4)2 =>
CaHPO4 + H3PO4 = Ca(H2PO4)2
Na + H2O = H2 + NaOH =>
2 Na + 2 H2O = H2 + 2 NaOH
KMnO4 + NaI + H2SO4 = MnSO4 + I2 + Na2SO4 + K2SO4 + H2O =>
2 KMnO4 + 10 NaI + 8 H2SO4 = 2 MnSO4 + 5 I2 + 5 Na2SO4 + K2SO4 + 8 H2O
Zn + Cu(NO3)2 = Zn2(NO3)2 + Cu2 =>
4 Zn + 2 Cu(NO3)2 = 2 Zn2(NO3)2 + Cu2
Cl2(g) + KI(s) = KCl(aq) + I2(s) =>
Cl2(g) + 2 KI(s) = 2 KCl(aq) + I2(s)
LiOH(aq) + Ba(NO3)2(aq) = Li(NO3)2(aq) + BaOH(s) =>
LiOH(aq) + Ba(NO3)2(aq) = Li(NO3)2(aq) + BaOH(s)
C6CH5COCl + CH3CH2COOH = C6H5COOH + CH3CH2COCl =>
4 C6CH5COCl + 5 CH3CH2COOH = 5 C6H5COOH + 4 CH3CH2COCl
H + PO3 + Ba(OH)2 = BaPO3 + H2O =>
2 H + PO3 + Ba(OH)2 = BaPO3 + 2 H2O
NaS + Pb(CH3COO)2 = PbS + Na(CH3COO)2 =>
NaS + Pb(CH3COO)2 = PbS + Na(CH3COO)2
LI(aq) = I(s) + L(g) =>
LI(aq) = I(s) + L(g)
NaS + Pb(CH3COO)2 = PbS + Na(CH3COO)2 =>
NaS + Pb(CH3COO)2 = PbS + Na(CH3COO)2
Cl2(g) + KI(s) = KCl(aq) + I2(s) =>
Cl2(g) + 2 KI(s) = 2 KCl(aq) + I2(s)
CS + I = CI + S =>
CS + I = CI + S
KOH + Cl2 = KClO3 + KCl + H2O =>
6 KOH + 3 Cl2 = KClO3 + 5 KCl + 3 H2O
KOH + HNO3 = KNO3 + HOH =>
KOH + HNO3 = KNO3 + HOH
VOCl2 + H2O = VO(OH)2 + HCl =>
VOCl2 + 2 H2O = VO(OH)2 + 2 HCl
MnCO3 = MnO + CO2 =>
MnCO3 = MnO + CO2
H + PO3 + Ba(OH)2 = BaPO3 + H2O =>
2 H + PO3 + Ba(OH)2 = BaPO3 + 2 H2O
HBr + Br(OH)2 = BrOH + H2O =>
HBr + 2 Br(OH)2 = 3 BrOH + H2O
NH4Cl = NH3 + HCl =>
NH4Cl = NH3 + HCl
C + SO2 = CS2 + CO =>
5 C + 2 SO2 = CS2 + 4 CO
KMnO4 + NaCl + H2SO4 = K2SO4 + Na2SO4 + Cl + MnSO4 + H2O =>
2 KMnO4 + 10 NaCl + 8 H2SO4 = K2SO4 + 5 Na2SO4 + 10 Cl + 2 MnSO4 + 8 H2O
(NH4)2SO4 + KOH = OHNH4 + K2SO4 =>
(NH4)2SO4 + 2 KOH = 2 OHNH4 + K2SO4
NH4Cl = NH3 + HCl =>
NH4Cl = NH3 + HCl
HgS + NO3 + H = [Hg(NO3)] + HS =>
HgS + NO3 + H = [Hg(NO3)] + HS
CH3CH2CHCHCH3 + HBr = CH3CH2CHCHBrCH3 + H2 =>
2 CH3CH2CHCHCH3 + 2 HBr = 2 CH3CH2CHCHBrCH3 + H2
K2 + CO3 = K2(CO3) =>
K2 + CO3 = K2(CO3)
KMnO4 + NaI + H2SO4 = MnSO4 + I2 + Na2SO4 + K2SO4 + H2O =>
2 KMnO4 + 10 NaI + 8 H2SO4 = 2 MnSO4 + 5 I2 + 5 Na2SO4 + K2SO4 + 8 H2O
S + E + X + O = SEXO =>
S + E + X + O = SEXO
Co3(PO4)2 + H2SO4 = CoSO4 + H3PO4 =>
Co3(PO4)2 + 3 H2SO4 = 3 CoSO4 + 2 H3PO4
H + PO3 + Ba(OH)2 = BaPO3 + H2O =>
2 H + PO3 + Ba(OH)2 = BaPO3 + 2 H2O
Hg + O2 = HgO =>
2 Hg + O2 = 2 HgO
C4H9Br + CuO + O2 = CuBr2 + CO2 + H2O =>
2 C4H9Br + CuO + 12 O2 = CuBr2 + 8 CO2 + 9 H2O
Cl2(g) + KI(s) = KCl(aq) + I2(s) =>
Cl2(g) + 2 KI(s) = 2 KCl(aq) + I2(s)
KMnO4 + NaCl + H2SO4 = K2SO4 + Na2SO4 + Cl + MnSO4 + H2O =>
2 KMnO4 + 10 NaCl + 8 H2SO4 = K2SO4 + 5 Na2SO4 + 10 Cl + 2 MnSO4 + 8 H2O
Cl2(g) + KI(s) = KCl(aq) + I2(s) =>
Cl2(g) + 2 KI(s) = 2 KCl(aq) + I2(s)
C2H6O + Cr2O7{2-} + H{+} = C2H4O + H2O + Cr3{+} =>
17 C2H6O + 3 Cr2O7{2-} + 8 H{+} = 17 C2H4O + 21 H2O + 2 Cr3{+}
CO2Ca(OH)2 = CaCO3H2O =>
CO2Ca(OH)2 = CaCO3H2O
C3H6O + SO2 + H2O = CH3SO3H + H2CO3 =>
3 C3H6O + 8 SO2 + 8 H2O = 8 CH3SO3H + H2CO3
K4[Fe(SCN)6] + K2Cr2O7 + H2SO4 = Fe2(SO4)3 + Cr2(SO4)3 + CO2 + H2O + K2SO4 + KNO3 =>
6 K4[Fe(SCN)6] + 97 K2Cr2O7 + 355 H2SO4 = 3 Fe2(SO4)3 + 97 Cr2(SO4)3 + 36 CO2 + 355 H2O + 91 K2SO4 + 36 KNO3
Al(s) + HBr(l) = AlBr3(s) + H2(g) =>
2 Al(s) + 6 HBr(l) = 2 AlBr3(s) + 3 H2(g)
H + PO3 + Ba(OH)2 = BaPO3 + H2O =>
2 H + PO3 + Ba(OH)2 = BaPO3 + 2 H2O
K3[Al(OH)6] = Al(OH)3 + KOH =>
K3[Al(OH)6] = Al(OH)3 + 3 KOH
NaCl + Zn(NO3)2 = Na(NO3)2 + ZnCl =>
NaCl + Zn(NO3)2 = Na(NO3)2 + ZnCl
KMnO4 + NaCl + H2SO4 = K2SO4 + Na2SO4 + Cl + MnSO4 + H2O =>
2 KMnO4 + 10 NaCl + 8 H2SO4 = K2SO4 + 5 Na2SO4 + 10 Cl + 2 MnSO4 + 8 H2O
CH3CH2CHCHCH3 + HBr = CH3CH2CHCHBrCH3 + H2 =>
2 CH3CH2CHCHCH3 + 2 HBr = 2 CH3CH2CHCHBrCH3 + H2
HI + CH3CH2OH = I + CH3CH2OH2 =>
HI + CH3CH2OH = I + CH3CH2OH2
KMnO4 + NaCl + H2SO4 = K2SO4 + Na2SO4 + Cl + MnSO4 + H2O =>
2 KMnO4 + 10 NaCl + 8 H2SO4 = K2SO4 + 5 Na2SO4 + 10 Cl + 2 MnSO4 + 8 H2O
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 02/17/24
Equations balanced on 03/18/23
Wyraź opinię o działaniu naszej aplikacji.