Equations balanced on the previous day | Equations balanced on the next day |
2 Na + CO3 = Na2CO3
HJ = H2 + J2 =>
2 HJ = H2 + J2
C12H15NCl + NaOH = NaClC12H15NOH =>
C12H15NCl + NaOH = NaClC12H15NOH
CsCl + BrF3 = CsBrF4 + BrF + Cl2 =>
2 CsCl + 3 BrF3 = 2 CsBrF4 + BrF + Cl2
CuSO4 = SO3 + CuO =>
CuSO4 = SO3 + CuO
CS2 + K2Cr2O7 + H2SO4 = CO2 + K2SO4 + Cr2(SO4)3 + H2O =>
3 CS2 + 8 K2Cr2O7 + 26 H2SO4 = 3 CO2 + 8 K2SO4 + 8 Cr2(SO4)3 + 26 H2O
SnCl2 + I2 = SnCl4 + SnI4 =>
2 SnCl2 + 2 I2 = SnCl4 + SnI4
As4O6 + FeS + O2 = FeAsO4 + SO2 =>
As4O6 + 4 FeS + 9 O2 = 4 FeAsO4 + 4 SO2
C6H807 + NaHCO = CO2 + H2O + Na3C6H507 =>
174 C6H807 + 831 NaHCO = 213 CO2 + 405 H2O + 277 Na3C6H507
FeSO4 + Pb(NO3)2 = Fe(NO3)2 + Pb(SO4) =>
FeSO4 + Pb(NO3)2 = Fe(NO3)2 + Pb(SO4)
C10H1O + O2 = CO2 + H2O =>
4 C10H1O + 39 O2 = 40 CO2 + 2 H2O
FeSO4 + K4[Fe(CN)6] = FeK4 + [Fe(CN)6]SO4 =>
FeSO4 + K4[Fe(CN)6] = FeK4 + [Fe(CN)6]SO4
C2H4 + OH = C2H4OH =>
C2H4 + OH = C2H4OH
NaCl + CaCO3 + C6H8O7 = H2O + NaCHO + CO2 + CaCl =>
18 NaCl + 18 CaCO3 + 5 C6H8O7 = 11 H2O + 18 NaCHO + 30 CO2 + 18 CaCl
Cu{2+} + CN{-} = Cu(CN)4{2-}{+} =>
Cu{2+} + 4 CN{-} = Cu(CN)4{2-}{+}
(NH4)2SO4 + KI = (NH4)I + K2SO4 =>
(NH4)2SO4 + 2 KI = 2(NH4)I + K2SO4
MgF2 + AlN = Mg3N2 + AlF3 =>
3 MgF2 + 2 AlN = Mg3N2 + 2 AlF3
Cu9Ni2Co3Fe4S16 + HNO3 = NO + Cu(NO3)2 + Ni(NO3)2 + Co(NO3)2 + S + H2O + Fe(NO3)3 =>
3 Cu9Ni2Co3Fe4S16 + 160 HNO3 = 40 NO + 27 Cu(NO3)2 + 6 Ni(NO3)2 + 9 Co(NO3)2 + 48 S + 80 H2O + 12 Fe(NO3)3
Fe(SCN)3 + NaF = Fe2F6 + NaSCN =>
2 Fe(SCN)3 + 6 NaF = Fe2F6 + 6 NaSCN
(CaSO4)2*H2O + H2O = CaSO4*2H2O =>
(CaSO4)2*H2O + 3 H2O = 2 CaSO4*2H2O
FeC2O4*2H2O + O2 = Fe2O2 + H2O + CO2 =>
2 FeC2O4*2H2O + O2 = Fe2O2 + 4 H2O + 4 CO2
ZnCl3 + Li2O = LiCl + Zn2O3 =>
2 ZnCl3 + 3 Li2O = 6 LiCl + Zn2O3
C5H10O5 + CO = C15H24 + CO2 =>
12 C5H10O5 + 90 CO = 5 C15H24 + 75 CO2
CuSO4 + Cl = CuCl2 + SO4 =>
CuSO4 + 2 Cl = CuCl2 + SO4
Fe(OH)3*4H2O = Fe2O3 + H2O =>
2 Fe(OH)3*4H2O = Fe2O3 + 11 H2O
NaOH + Cl2O5 = NaClO3 + H2O =>
2 NaOH + Cl2O5 = 2 NaClO3 + H2O
NaH + H2O2 = NaOH + H2O =>
NaH + H2O2 = NaOH + H2O
Ba(OH)2 + H3BO3 = Ba(B(OH)4)2 =>
Ba(OH)2 + 2 H3BO3 = Ba(B(OH)4)2
C6H5OCH3 + Br2 = C7H6Br2O + HBr =>
C6H5OCH3 + 2 Br2 = C7H6Br2O + 2 HBr
Li + H2O = LiOH + H2 =>
2 Li + 2 H2O = 2 LiOH + H2
Cu(OH)(NO3) + NH4NO3 + NH4OH = Cu(NH3)4(NO3)2 + H2O =>
Cu(OH)(NO3) + NH4NO3 + 3 NH4OH = Cu(NH3)4(NO3)2 + 4 H2O
NaCl + SO2 + O2 + H2O = Na2(SO4) + HCl =>
4 NaCl + 2 SO2 + O2 + 2 H2O = 2 Na2(SO4) + 4 HCl
NiSO4*7H2O + Na2CO3 = NiCO3 + Na2SO4 + H2O =>
NiSO4*7H2O + Na2CO3 = NiCO3 + Na2SO4 + 7 H2O
CH3CH2OH + O2 = H2O + (CH3COOH) =>
CH3CH2OH + O2 = H2O + (CH3COOH)
CH3CH2O + O2 = CH3COOH + H2O =>
4 CH3CH2O + 3 O2 = 4 CH3COOH + 2 H2O
(CH3)2CHO + KMnO4 = CO2 + H2O + MnO2 + KOH =>
3(CH3)2CHO + 17 KMnO4 = 9 CO2 + 2 H2O + 17 MnO2 + 17 KOH
HCl(aq) + CaCO3(s) = H2CO3(s) + CaCl2(aq) =>
2 HCl(aq) + CaCO3(s) = H2CO3(s) + CaCl2(aq)
NO(g) + Br2(g) = NOBr(g) =>
2 NO(g) + Br2(g) = 2 NOBr(g)
CU(OH)2 = CUOH2O =>
CU(OH)2 = CUOH2O
NaCl + Hg2SO4 = Hg2Cl2 + Na2SO4 =>
2 NaCl + Hg2SO4 = Hg2Cl2 + Na2SO4
K2Cr2O7 + H2SO4 + HCl = Cr2(SO4)3 + K2SO4 + H2O + Cl2 =>
K2Cr2O7 + 4 H2SO4 + 6 HCl = Cr2(SO4)3 + K2SO4 + 7 H2O + 3 Cl2
(H)2 + (I)2 = HI =>
(H)2 + (I)2 = 2 HI
CH3Cl + NaOH = C4H8 + NaCl + H2O =>
4 CH3Cl + 4 NaOH = C4H8 + 4 NaCl + 4 H2O
Al2S3 + CaCO3 = CaS + Al2(CO3)3 =>
Al2S3 + 3 CaCO3 = 3 CaS + Al2(CO3)3
LiCl + Ba(NO3)2 = Li(NO3) + BaCl2 =>
2 LiCl + Ba(NO3)2 = 2 Li(NO3) + BaCl2
CalciumHydroxide + Chromium(III)Nitrate = CalciumNitrate + Chromium(III)Hydroxide =>
CalciumHydroxide + Chromium(III)Nitrate = CalciumNitrate + Chromium(III)Hydroxide
HCl + NaBrO3 + NaBr = Br2 + H2O + NaCl =>
6 HCl + NaBrO3 + 5 NaBr = 3 Br2 + 3 H2O + 6 NaCl
Fe(OH)3 + NaClO + KOH = K2FeO4 + NaCl + H2O =>
2 Fe(OH)3 + 3 NaClO + 4 KOH = 2 K2FeO4 + 3 NaCl + 5 H2O
Na[Al(OH)4] + HCl = Al(OH)3 + NaCl + H2O =>
Na[Al(OH)4] + HCl = Al(OH)3 + NaCl + H2O
(NH3) + H2SO4 = (NH4)2SO4 =>
2(NH3) + H2SO4 = (NH4)2SO4
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 05/27/24
Equations balanced on 06/26/23
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