Equations balanced on the previous day | Equations balanced on the next day |
B2H6 + 6 H2O = 2 H2BO3 + 7 H2
C3Cl3N3O3 + HCl = Cl + C3N3O3H3 =>
C3Cl3N3O3 + 3 HCl = 6 Cl + C3N3O3H3
Na2Cr2O7 + KHSO3 + H2SO4 = Cr2(SO4)3 + Na2SO4 + H2O + K2SO4 =>
2 Na2Cr2O7 + 6 KHSO3 + 5 H2SO4 = 2 Cr2(SO4)3 + 2 Na2SO4 + 8 H2O + 3 K2SO4
SnCl2 + H2O = Sn(OH)Cl + H2 + Cl2 =>
2 SnCl2 + 2 H2O = 2 Sn(OH)Cl + H2 + Cl2
NaOH + H2SO4 = Na2(HSO4)2 + H2O =>
2 NaOH + 2 H2SO4 = Na2(HSO4)2 + 2 H2O
Ba(OH)2 + H(ClO4) = Ba(ClO4)2 + H2O =>
Ba(OH)2 + 2 H(ClO4) = Ba(ClO4)2 + 2 H2O
Re + O = ReO2 =>
Re + 2 O = ReO2
H3C6H507 + NaHCO3 = NaC6H507 + H2O + CO2 =>
266 H3C6H507 + 267 NaHCO3 = 267 NaC6H507 + 279 H2O + 261 CO2
ZnO + AlCl3 = ZnCl3 + Al3O3 =>
3 ZnO + 3 AlCl3 = 3 ZnCl3 + Al3O3
AgF(aq)NH4Cl(aq) = AgCl(s)NH4F(aq) =>
AgF(aq)NH4Cl(aq) = AgCl(s)NH4F(aq)
Ti + PdCl2 = TiCl4 + Pd =>
Ti + 2 PdCl2 = TiCl4 + 2 Pd
HCOOH = H + COO =>
HCOOH = 2 H + COO
C14H10O2 + NaBH4 + CH3OH = C14H14O2 + NaB(OH)3 =>
23 C14H10O2 + 8 NaBH4 + 28 CH3OH = 25 C14H14O2 + 8 NaB(OH)3
H2 + Ce = HCe =>
H2 + 2 Ce = 2 HCe
(NaOH) + CO2 = NaHCO3 =>
(NaOH) + CO2 = NaHCO3
NaSO4 + H2O = NaSO4H2O =>
NaSO4 + H2O = NaSO4H2O
HNO3 + FeS = FeNO3 + HS =>
HNO3 + FeS = FeNO3 + HS
Ba(OH)2 + H(ClO4) = Ba(ClO4)2 + H2O =>
Ba(OH)2 + 2 H(ClO4) = Ba(ClO4)2 + 2 H2O
HNO3 + FeS = FeNO3 + HS =>
HNO3 + FeS = FeNO3 + HS
NH3 + I2 = N2I6 + H2 =>
2 NH3 + 3 I2 = N2I6 + 3 H2
C6H5CHCH2 + CH3COCH3 + NH3 + HCl = C10H15NHCl + H2O =>
C6H5CHCH2 + 4 CH3COCH3 + 2 NH3 + 2 HCl = 2 C10H15NHCl + 4 H2O
C6H5CHCH2 + CH3COCH3 + NH3 + HCl = C10H15NHCl + H2O =>
C6H5CHCH2 + 4 CH3COCH3 + 2 NH3 + 2 HCl = 2 C10H15NHCl + 4 H2O
Br2 + NaI2 = I2 + NaBr2 =>
Br2 + NaI2 = I2 + NaBr2
FePO4(s) + H3O(aq) = Fe(aq) + H3PO(aq) + H2O(l) =>
FePO4(s) + 9 H3O(aq) = Fe(aq) + H3PO(aq) + 12 H2O(l)
NaAlO2 + HCl = AlCl3 + NaH3O2 =>
NaAlO2 + 3 HCl = AlCl3 + NaH3O2
FeCl2 + ClF4 = FeF3 + Cl2 =>
8 FeCl2 + 6 ClF4 = 8 FeF3 + 11 Cl2
C6H5CHCH2 + CH3COCH3 + NH3 + HCl = C10H15NHCl + H2O =>
C6H5CHCH2 + 4 CH3COCH3 + 2 NH3 + 2 HCl = 2 C10H15NHCl + 4 H2O
NaAlO2 + HCl = AlCl3 + NaH3O2 =>
NaAlO2 + 3 HCl = AlCl3 + NaH3O2
Ba(OH)2 + H(ClO4) = Ba(ClO4)2 + H2O =>
Ba(OH)2 + 2 H(ClO4) = Ba(ClO4)2 + 2 H2O
H{+} + Cr2O7{-2} + H2S = Cr{3+} + S + H2O =>
8 H{+} + Cr2O7{-2} + 3 H2S = 2 Cr{3+} + 3 S + 7 H2O
C6H5CHCH2 + CH3COCH3 + NH3 + HCl = C10H15NHCl + H2O =>
C6H5CHCH2 + 4 CH3COCH3 + 2 NH3 + 2 HCl = 2 C10H15NHCl + 4 H2O
C6H5CHCH2 + CH3COCH3 + NH3 + HCl = C10H15NHCl + H2O =>
C6H5CHCH2 + 4 CH3COCH3 + 2 NH3 + 2 HCl = 2 C10H15NHCl + 4 H2O
HNO3 + FeS = FeNO3 + HS =>
HNO3 + FeS = FeNO3 + HS
C6H6 + H2O = CH4 + CO2 =>
4 C6H6 + 18 H2O = 15 CH4 + 9 CO2
C6H5CHCH2 + CH3COCH3 + NH3 + HCl = C10H15NHCl + H2O =>
C6H5CHCH2 + 4 CH3COCH3 + 2 NH3 + 2 HCl = 2 C10H15NHCl + 4 H2O
Fe2O3(s) + Al(s) = Fe(l) + Al2O3(s) =>
Fe2O3(s) + 2 Al(s) = 2 Fe(l) + Al2O3(s)
H3AsO4 + Pb(NO3)2 = HNO3 + PbHAsO4 =>
H3AsO4 + Pb(NO3)2 = 2 HNO3 + PbHAsO4
H2S + NO3 = NO + H2O + S =>
2 H2S + NO3 = NO + 2 H2O + 2 S
NaCl + Li2SO4 = NaSO4 + Li2Cl =>
NaCl + Li2SO4 = NaSO4 + Li2Cl
H3AsO4 + Pb(NO3)2 = HNO3 + PbHAsO4 =>
H3AsO4 + Pb(NO3)2 = 2 HNO3 + PbHAsO4
NaAlO2 + HCl = AlCl3 + NaH3O2 =>
NaAlO2 + 3 HCl = AlCl3 + NaH3O2
Al2O3(s) + NaOH(aq) + H2O(l) = NaAl(OH)4 =>
Al2O3(s) + 2 NaOH(aq) + 3 H2O(l) = 2 NaAl(OH)4
NaAlO2 + HCl = AlCl3 + NaH3O2 =>
NaAlO2 + 3 HCl = AlCl3 + NaH3O2
C6H5NO2 + Zn + NaOH = Na2ZnO2 + C6H5NH2 + H2O =>
C6H5NO2 + 3 Zn + 6 NaOH = 3 Na2ZnO2 + C6H5NH2 + 2 H2O
C6H5CHCH2 + CH3COCH3 + NH3 + HCl = C10H15NHCl + H2O =>
C6H5CHCH2 + 4 CH3COCH3 + 2 NH3 + 2 HCl = 2 C10H15NHCl + 4 H2O
Rb(s) + Zn(NO3)2(aq) = RbNO3 + Zn2 =>
4 Rb(s) + 2 Zn(NO3)2(aq) = 4 RbNO3 + Zn2
CuOCu + O2 = CuO =>
2 CuOCu + O2 = 4 CuO
NaAlO2 + HCl = AlCl3 + NaH3O2 =>
NaAlO2 + 3 HCl = AlCl3 + NaH3O2
NO2 = O2 + N =>
NO2 = O2 + N
K4Fe(CN)6 + KMnO4 + H2SO4 = KHSO4 + Fe2(SO4)3 + MnSO4 + HNO3 + CO2 + H2O =>
10 K4Fe(CN)6 + 122 KMnO4 + 299 H2SO4 = 162 KHSO4 + 5 Fe2(SO4)3 + 122 MnSO4 + 60 HNO3 + 60 CO2 + 188 H2O
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 11/19/23
Equations balanced on 12/19/22
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