Equations balanced on the previous day | Equations balanced on the next day |
2 C4H3 + 7 H2 = 2 C4H10
Cd(s) + HCl(aq) = H2Cd + Cl =>
Cd(s) + 2 HCl(aq) = H2Cd + 2 Cl
Cu2(OAc)4*H2O + C2H8N2 + KI + H2O = [Cu(H2NCH2CH2NH2)2(H2O)2]I2 + K(OAc) =>
Cu2(OAc)4*H2O + 4 C2H8N2 + 4 KI + 3 H2O = 2[Cu(H2NCH2CH2NH2)2(H2O)2]I2 + 4 K(OAc)
F2 + I2 = FI =>
F2 + I2 = 2 FI
CH3CH(CH3)CH2COOH + NaOH = CH3CH(CH3)CH2COONa + H2O =>
CH3CH(CH3)CH2COOH + NaOH = CH3CH(CH3)CH2COONa + H2O
HBr(aq) + Sr(s) + OH = SrBr + H2O =>
HBr(aq) + Sr(s) + OH = SrBr + H2O
MnCl2 + Br + NH4OH = Mn2O4 + NH4Cl + NH4Br + H2O =>
2 MnCl2 + 4 Br + 8 NH4OH = Mn2O4 + 4 NH4Cl + 4 NH4Br + 4 H2O
KMnO4 + H2C2O4 + H2SO4 = MnSO4 + K2SO4 + CO2 + H2O =>
2 KMnO4 + 5 H2C2O4 + 3 H2SO4 = 2 MnSO4 + K2SO4 + 10 CO2 + 8 H2O
KMnO4 + HCl + K4[Fe(CN6)] = K3[Fe(CN6)] + KCl + MnCl2 + H2O =>
KMnO4 + 8 HCl + 5 K4[Fe(CN6)] = 5 K3[Fe(CN6)] + 6 KCl + MnCl2 + 4 H2O
CoI2 + H2O = CoO + HI =>
CoI2 + H2O = CoO + 2 HI
Al(ClO3) = AlClO3 =>
Al(ClO3) = AlClO3
K4Fe(CN)6 + H2SO4 + H2O = K2SO4 + FeSO4 + (NH4)2SO4 + CO =>
K4Fe(CN)6 + 6 H2SO4 + 6 H2O = 2 K2SO4 + FeSO4 + 3(NH4)2SO4 + 6 CO
NaOH(aq) + K2SO4(aq) = KOH(s) + Na2SO4(s) =>
2 NaOH(aq) + K2SO4(aq) = 2 KOH(s) + Na2SO4(s)
KClO3 + FeCl2 = Fe(ClO3)2 + KCl =>
2 KClO3 + FeCl2 = Fe(ClO3)2 + 2 KCl
NH3 + KMnO4 + KOH = N2 + K2MnO4 + H2O =>
2 NH3 + 6 KMnO4 + 6 KOH = N2 + 6 K2MnO4 + 6 H2O
BiONO3 + Na2[Sn(OH)4] + NaOH + H2O = Bi + Na2[Sn(OH)6] + NaN33 =>
66 BiONO3 + 265 Na2[Sn(OH)4] + 2 NaOH + 264 H2O = 66 Bi + 265 Na2[Sn(OH)6] + 2 NaN33
MnCl2 + Br + NH4OH = Mn2O4 + NH4Cl + NH4Br + H2O =>
2 MnCl2 + 4 Br + 8 NH4OH = Mn2O4 + 4 NH4Cl + 4 NH4Br + 4 H2O
KF + Mg(OH)2 = KOH + MgF2 =>
2 KF + Mg(OH)2 = 2 KOH + MgF2
CH4 = C + H =>
CH4 = C + 4 H
C + NH4OH + C7H16 = C20H23N + O2 =>
97 C + 8 NH4OH + 9 C7H16 = 8 C20H23N + 4 O2
BaOH + Na3PO4 = Na3OH + BaPO4 =>
BaOH + Na3PO4 = Na3OH + BaPO4
SnS + KOH = K2SnO2 + H2S =>
SnS + 2 KOH = K2SnO2 + H2S
HBr(aq) + Sr(s) + OH = SrBr + H2O =>
HBr(aq) + Sr(s) + OH = SrBr + H2O
C + NH4OH + C7H16 = C20H23N + O2 =>
97 C + 8 NH4OH + 9 C7H16 = 8 C20H23N + 4 O2
HNO3 + HCl + HgS = S2 + HgCl2 + NO + H2O =>
4 HNO3 + 12 HCl + 6 HgS = 3 S2 + 6 HgCl2 + 4 NO + 8 H2O
C + NH4OH + C7H16 = C20H23N + O2 =>
97 C + 8 NH4OH + 9 C7H16 = 8 C20H23N + 4 O2
HNO3 + HCl + HgS = S2 + HgCl2 + NO + H2O =>
4 HNO3 + 12 HCl + 6 HgS = 3 S2 + 6 HgCl2 + 4 NO + 8 H2O
SnS + KOH = K2SnO2 + H2S =>
SnS + 2 KOH = K2SnO2 + H2S
HNO3 + HCl + HgS = S2 + HgCl2 + NO + H2O =>
4 HNO3 + 12 HCl + 6 HgS = 3 S2 + 6 HgCl2 + 4 NO + 8 H2O
SrCl2 + Co(NO3)2 = SrNO3 + Co(Cl2)2 =>
2 SrCl2 + Co(NO3)2 = 2 SrNO3 + Co(Cl2)2
HNO3 + HCl + HgS = S2 + HgCl2 + NO + H2O =>
4 HNO3 + 12 HCl + 6 HgS = 3 S2 + 6 HgCl2 + 4 NO + 8 H2O
Nb2O5 + CCl4 = CO2 + NbCl5 =>
2 Nb2O5 + 5 CCl4 = 5 CO2 + 4 NbCl5
HNO3 + HCl + HgS = S2 + HgCl2 + NO + H2O =>
4 HNO3 + 12 HCl + 6 HgS = 3 S2 + 6 HgCl2 + 4 NO + 8 H2O
MnCl2 + Br + NH4OH = Mn2O4 + NH4Cl + NH4Br + H2O =>
2 MnCl2 + 4 Br + 8 NH4OH = Mn2O4 + 4 NH4Cl + 4 NH4Br + 4 H2O
C + NH4OH + C7H16 = C20H23N + O2 =>
97 C + 8 NH4OH + 9 C7H16 = 8 C20H23N + 4 O2
BaOH + Na3PO4 = Na3OH + BaPO4 =>
BaOH + Na3PO4 = Na3OH + BaPO4
AlCl3 + Zn = ZnCl3 + Al =>
AlCl3 + Zn = ZnCl3 + Al
MgBr2 = Br + Mg =>
MgBr2 = 2 Br + Mg
(NH4)2CO3(s) + HCl(aq) = NH4Cl(aq) + H2O(l) + CO2(g) =>
(NH4)2CO3(s) + 2 HCl(aq) = 2 NH4Cl(aq) + H2O(l) + CO2(g)
BaOH + Na3PO4 = Na3OH + BaPO4 =>
BaOH + Na3PO4 = Na3OH + BaPO4
HBr(aq) + Sr(s) + OH = SrBr + H2O =>
HBr(aq) + Sr(s) + OH = SrBr + H2O
C4H10O + O2 = CO2 + H2O =>
C4H10O + 6 O2 = 4 CO2 + 5 H2O
HNO3 + HCl + HgS = S2 + HgCl2 + NO + H2O =>
4 HNO3 + 12 HCl + 6 HgS = 3 S2 + 6 HgCl2 + 4 NO + 8 H2O
Na3PO4(aq) + CuCl2(aq) = NaCl(aq) + Cu3(PO4)2(aq) =>
2 Na3PO4(aq) + 3 CuCl2(aq) = 6 NaCl(aq) + Cu3(PO4)2(aq)
BaOH + Na3PO4 = Na3OH + BaPO4 =>
BaOH + Na3PO4 = Na3OH + BaPO4
SnS + KOH = K2SnO2 + H2S =>
SnS + 2 KOH = K2SnO2 + H2S
H2S + AsCl3 = HCl + As2S3 =>
3 H2S + 2 AsCl3 = 6 HCl + As2S3
C4H8Br + H2O = C4H10O + Br2 =>
2 C4H8Br + 2 H2O = 2 C4H10O + Br2
KMnO4 + Na2SO3 + H2SO4 = MnSO3 + Na2SO4 + K2SO4 + H2O =>
2 KMnO4 + 7 Na2SO3 + 3 H2SO4 = 2 MnSO3 + 7 Na2SO4 + K2SO4 + 3 H2O
BaOH + Na3PO4 = Na3OH + BaPO4 =>
BaOH + Na3PO4 = Na3OH + BaPO4
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 11/19/23
Equations balanced on 12/19/22
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