Equations balanced on the previous day | Equations balanced on the next day |
2 Al + 3 SiO3 = Al2(SiO3)3
KMnO4 + TiCl3 + H2O = MnO2 + TiOCl2 + HCl + KOH =>
KMnO4 + 3 TiCl3 + 2 H2O = MnO2 + 3 TiOCl2 + 3 HCl + KOH
C3H4N2 + H2O = C3H5N2 + OH =>
C3H4N2 + H2O = C3H5N2 + OH
FeCl3 + Fe(H2PO4)2 = Fe(H2PO4)3 + FeCl2 =>
2 FeCl3 + 3 Fe(H2PO4)2 = 2 Fe(H2PO4)3 + 3 FeCl2
Na2SO3(aq) + Cd(NO3)(aq) = Na2NO3(aq) + CdSO3(s) =>
Na2SO3(aq) + Cd(NO3)(aq) = Na2NO3(aq) + CdSO3(s)
H2 + O2 = H2O =>
2 H2 + O2 = 2 H2O
K2Cr2O7 + H202 = KOH + Cr2O3 + O2 =>
101 K2Cr2O7 + H202 = 202 KOH + 101 Cr2O3 + 101 O2
HClO4 + NaOH = NaClO4 + H2O =>
HClO4 + NaOH = NaClO4 + H2O
ICl + Fe = FeCl2 + I2 =>
2 ICl + Fe = FeCl2 + I2
FeCl3 + Fe(H2PO4)2 = Fe(H2PO4)3 + FeCl2 =>
2 FeCl3 + 3 Fe(H2PO4)2 = 2 Fe(H2PO4)3 + 3 FeCl2
FeCl3 + Fe(H2PO4)2 = Fe(H2PO4)3 + FeCl2 =>
2 FeCl3 + 3 Fe(H2PO4)2 = 2 Fe(H2PO4)3 + 3 FeCl2
FeCl3 + Fe(H2PO4)2 = Fe(H2PO4)3 + FeCl2 =>
2 FeCl3 + 3 Fe(H2PO4)2 = 2 Fe(H2PO4)3 + 3 FeCl2
Na2MoO4 + HCl = MoO4 + NaCl + H2 =>
Na2MoO4 + 2 HCl = MoO4 + 2 NaCl + H2
C3H8 + O2 = CO2 + H2O =>
C3H8 + 5 O2 = 3 CO2 + 4 H2O
N2 + NH4 = N(NH4)3 =>
N2 + 6 NH4 = 2 N(NH4)3
C6H5COOH + KOH = H2O + KC6H5COO =>
C6H5COOH + KOH = H2O + KC6H5COO
K2Cr2O7 + H202 = KOH + Cr2O3 + O2 =>
101 K2Cr2O7 + H202 = 202 KOH + 101 Cr2O3 + 101 O2
K2Cr2O7 + H202 = KOH + Cr2O3 + O2 =>
101 K2Cr2O7 + H202 = 202 KOH + 101 Cr2O3 + 101 O2
SiO2 + NaHCO3 = Na2OSiO2 + H2O + CO2 =>
SiO2 + 2 NaHCO3 = Na2OSiO2 + H2O + 2 CO2
Li2CO3 + BaBr2 = BaCO3 + LiBr =>
Li2CO3 + BaBr2 = BaCO3 + 2 LiBr
FeCl3 + Fe(H2PO4)2 = Fe(H2PO4)3 + FeCl2 =>
2 FeCl3 + 3 Fe(H2PO4)2 = 2 Fe(H2PO4)3 + 3 FeCl2
K2Cr2O7 + H202 = KOH + Cr2O3 + O2 =>
101 K2Cr2O7 + H202 = 202 KOH + 101 Cr2O3 + 101 O2
LiOH + HCl = LiCl + HOH =>
LiOH + HCl = LiCl + HOH
FeCl3 + Fe(H2PO4)2 = Fe(H2PO4)3 + FeCl2 =>
2 FeCl3 + 3 Fe(H2PO4)2 = 2 Fe(H2PO4)3 + 3 FeCl2
Br({-}) + I2 = I({-}) + Br2 =>
2 Br({-}) + I2 = 2 I({-}) + Br2
FeCl3 + Fe(H2PO4)2 = Fe(H2PO4)3 + FeCl2 =>
2 FeCl3 + 3 Fe(H2PO4)2 = 2 Fe(H2PO4)3 + 3 FeCl2
K2Cr2O7 + H202 = KOH + Cr2O3 + O2 =>
101 K2Cr2O7 + H202 = 202 KOH + 101 Cr2O3 + 101 O2
PB(No3)2 + NaCl = PBCl + Na(No3)2 =>
PB(No3)2 + NaCl = PBCl + Na(No3)2
BCl3 + H2O = B(OH)3(aq) + HCl =>
BCl3 + 3 H2O = B(OH)3(aq) + 3 HCl
FeCl3 + Fe(H2PO4)2 = Fe(H2PO4)3 + FeCl2 =>
2 FeCl3 + 3 Fe(H2PO4)2 = 2 Fe(H2PO4)3 + 3 FeCl2
C7H10ClN3O3 + H2O2 = CO2 + H2O + NO3{-} + H{+} + Cl{-} =>
C7H10ClN3O3 + 23 H2O2 = 7 CO2 + 26 H2O + 3 NO3{-} + 4 H{+} + Cl{-}
KBr + AgClO4 = KClO4 + AgBr =>
KBr + AgClO4 = KClO4 + AgBr
FeCl3 + Fe(H2PO4)2 = Fe(H2PO4)3 + FeCl2 =>
2 FeCl3 + 3 Fe(H2PO4)2 = 2 Fe(H2PO4)3 + 3 FeCl2
K2Cr2O7 + H202 = KOH + Cr2O3 + O2 =>
101 K2Cr2O7 + H202 = 202 KOH + 101 Cr2O3 + 101 O2
HN3 + HNO3 = N2 + NH4NO3 =>
3 HN3 + HNO3 = 4 N2 + NH4NO3
C6H6O + FeCl3 = C6H5OFeCl2 + HCl =>
C6H6O + FeCl3 = C6H5OFeCl2 + HCl
C5H8(s) + O2(g) = CO2(g) + H2O(g) =>
C5H8(s) + 7 O2(g) = 5 CO2(g) + 4 H2O(g)
CuSCN + KIO3 + HCl = CuSO4 + ICl + HCN + KCl + H2O =>
4 CuSCN + 7 KIO3 + 14 HCl = 4 CuSO4 + 7 ICl + 4 HCN + 7 KCl + 5 H2O
Al2(SO4)3 + Ba(Cl2)2 = Al(Cl2)3 + BaSO4 =>
Al2(SO4)3 + 3 Ba(Cl2)2 = 2 Al(Cl2)3 + 3 BaSO4
K2Cr2O7 + H202 = KOH + Cr2O3 + O2 =>
101 K2Cr2O7 + H202 = 202 KOH + 101 Cr2O3 + 101 O2
NaBr + KMn04 = NaMn04 + KBr =>
NaBr + KMn04 = NaMn04 + KBr
H202 + MgO2 = O + HMg =>
H202 + 202 MgO2 = 404 O + 202 HMg
FeCl3 + H2S = FeCl2 + HCl + S =>
2 FeCl3 + H2S = 2 FeCl2 + 2 HCl + S
CuOSO3 = CuSO4 =>
CuOSO3 = CuSO4
Cl2 + NH4F = ClNH4 + F =>
Cl2 + 2 NH4F = 2 ClNH4 + 2 F
FeCO3 + H2SO4 = Fe(SO4)3 + SO2 + CO2 + H2O =>
FeCO3 + 5 H2SO4 = Fe(SO4)3 + 2 SO2 + CO2 + 5 H2O
K + [Fe(CN)6] + Fe = KFe[Fe(CN)6] =>
K + [Fe(CN)6] + Fe = KFe[Fe(CN)6]
K2Cr2O7 + H202 = KOH + Cr2O3 + O2 =>
101 K2Cr2O7 + H202 = 202 KOH + 101 Cr2O3 + 101 O2
K2Cr2O7 + Fe304 + H2SO4 = K2SO4 + Cr2(SO4)3 + Fe(SO4)3 + H2O =>
304 K2Cr2O7 + Fe304 + 2128 H2SO4 = 304 K2SO4 + 304 Cr2(SO4)3 + 304 Fe(SO4)3 + 2128 H2O
NaHSO3 + HI = NaI + H2SO3 =>
NaHSO3 + HI = NaI + H2SO3
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 02/22/24
Equations balanced on 03/23/23
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