Equations balanced on the previous day | Equations balanced on the next day |
2 C3H6 + 5 Ag(NH3)2O = 5 Ag + 2 C3H5O2 + H2O + 10 NH3
NO2 + Ca = CaO + Ca3N2 =>
2 NO2 + 7 Ca = 4 CaO + Ca3N2
NaClO + As2O3 = As2O5 + NaCl =>
2 NaClO + As2O3 = As2O5 + 2 NaCl
AgNO3 + NaOAc = AgOAc + NaNO3 =>
AgNO3 + NaOAc = AgOAc + NaNO3
CCl4 + HF2 = HCl2 + CF2Cl2 =>
CCl4 + HF2 = HCl2 + CF2Cl2
C + O2 = CO =>
2 C + O2 = 2 CO
C2H5OH + NaMnO4 + NaOH = CH3COOH + Na2MnO4 + H2O =>
C2H5OH + 4 NaMnO4 + 4 NaOH = CH3COOH + 4 Na2MnO4 + 3 H2O
HCl + KMnO4 + H2SO4 = Cl2 + MnSO4 + KOH + H2O =>
10 HCl + 2 KMnO4 + 2 H2SO4 = 5 Cl2 + 2 MnSO4 + 2 KOH + 6 H2O
NaS + Hg(NO3) = HgS + Na(NO3) =>
NaS + Hg(NO3) = HgS + Na(NO3)
AgNO3 + NaSO4 = AgSO4NaNO3 =>
AgNO3 + NaSO4 = AgSO4NaNO3
As2O5 + NaOH = As(OH)5 + Na2O =>
As2O5 + 10 NaOH = 2 As(OH)5 + 5 Na2O
KCN + H2O = K{+} + HCN + OH{-} =>
KCN + H2O = K{+} + HCN + OH{-}
Zn() + H2SO4() = ZnSO4() + H2() =>
Zn() + H2SO4() = ZnSO4() + H2()
PH3 + KMnO4 = K3PO4 + K2HPO4 + MnO2 + H2O =>
3 PH3 + 8 KMnO4 = 2 K3PO4 + K2HPO4 + 8 MnO2 + 4 H2O
Fe(OH)3(aq) + H2SO4(aq) = Fe2(SO4)3(aq) + H2O(l) =>
2 Fe(OH)3(aq) + 3 H2SO4(aq) = Fe2(SO4)3(aq) + 6 H2O(l)
NIS + CO = NI + CO2 + CS2 =>
2 NIS + 2 CO = 2 NI + CO2 + CS2
Ba + F = Ba2F =>
2 Ba + F = Ba2F
AgCl + KI = Ag + KCl + I =>
AgCl + KI = Ag + KCl + I
KMnO4 + H2SO4 + H2SO3 = KHSO4 + Mn(HSO4)3 + H2O =>
KMnO4 + 2 H2SO4 + 2 H2SO3 = KHSO4 + Mn(HSO4)3 + 2 H2O
Sn2Cl4 + Cr = Cr2Cl3 + Sn4 =>
6 Sn2Cl4 + 16 Cr = 8 Cr2Cl3 + 3 Sn4
H2S(aq) + O2(g) = S(s) + H2O(g) =>
2 H2S(aq) + O2(g) = 2 S(s) + 2 H2O(g)
KMnO4 + H2C2O4 + CH3COOH = MnC2O4 + CH3COOK + H2O =>
6 KMnO4 + H2C2O4 + 11 CH3COOH = 6 MnC2O4 + 6 CH3COOK + 14 H2O
(CH2)4(COOH)2 + H2 = (HOCH2(CH2)4CH2OH) + CO2 =>
5(CH2)4(COOH)2 + 3 H2 = 4(HOCH2(CH2)4CH2OH) + 6 CO2
FeSO4 + NO = FeO2 + N2SO4 =>
FeSO4 + 2 NO = FeO2 + N2SO4
BaCl + Na(OH) = NaCl + Ba(OH) =>
BaCl + Na(OH) = NaCl + Ba(OH)
K4[Fe(CN)6] + KClO3 + HCl = K3[Fe(CN)6] + KCl + H2O =>
6 K4[Fe(CN)6] + KClO3 + 6 HCl = 6 K3[Fe(CN)6] + 7 KCl + 3 H2O
KCl + MnO2 = KClO4 + Mn =>
KCl + 2 MnO2 = KClO4 + 2 Mn
K2Cl2 + H2SO4 = K2SO4 + HCl =>
K2Cl2 + H2SO4 = K2SO4 + 2 HCl
Sb(SO4)3 + NaOH = Sb(OH)3 + Na(SO4) =>
Sb(SO4)3 + 3 NaOH = Sb(OH)3 + 3 Na(SO4)
C3H9NO2 + H2 = C3H9N + H2O =>
C3H9NO2 + 2 H2 = C3H9N + 2 H2O
(CH2)4(COOH)2 + H2 = (HOCH2(CH2)4CH2OH) + CO2 =>
5(CH2)4(COOH)2 + 3 H2 = 4(HOCH2(CH2)4CH2OH) + 6 CO2
HgS2 + Fe = Fe2S3 + Hg =>
3 HgS2 + 4 Fe = 2 Fe2S3 + 3 Hg
BaO2(s) + HCl = H2O2 + BaCl2 =>
BaO2(s) + 2 HCl = H2O2 + BaCl2
(CH2)4(COOH)2 + H2 = (HOCH2(CH2)4CH2OH) + CO2 =>
5(CH2)4(COOH)2 + 3 H2 = 4(HOCH2(CH2)4CH2OH) + 6 CO2
Al + NaNO3 + NaOH = Na2AlO2 + NH3 + H2O =>
4 Al + NaNO3 + 7 NaOH = 4 Na2AlO2 + NH3 + 2 H2O
NaCO3{-} + HCl = NaCl + HCO3{-} =>
NaCO3{-} + HCl = NaCl + HCO3{-}
Ba2 + F = Ba2F =>
Ba2 + F = Ba2F
C + O = CO10 =>
C + 10 O = CO10
Fe(NH4)2(SO4)26H2O + H2C2O4 + K2C2O4 + H2O2 = K3Fe(C2O4)34H2O + (NH4)2SO4 + H2SO4 + H2O =>
2 Fe(NH4)2(SO4)26H2O + 65 H2C2O4 + 3 K2C2O4 + 15 H2O2 = 2 K3Fe(C2O4)34H2O + 2(NH4)2SO4 + 50 H2SO4 + 30 H2O
Pb(C4H4O6) + BaS + H2O = BaO + PbS + H2(C4H4O6) =>
Pb(C4H4O6) + BaS + H2O = BaO + PbS + H2(C4H4O6)
(CH2)4(COOH)2 + H2 = (HOCH2(CH2)4CH2OH) + CO2 =>
5(CH2)4(COOH)2 + 3 H2 = 4(HOCH2(CH2)4CH2OH) + 6 CO2
BaNO3 = Ba + NO3 =>
BaNO3 = Ba + NO3
(CH2)4(COOH)2 + H2 = (HOCH2(CH2)4CH2OH) + CO2 =>
5(CH2)4(COOH)2 + 3 H2 = 4(HOCH2(CH2)4CH2OH) + 6 CO2
(CH2)4(COOH)2 + H2 = (HOCH2(CH2)4CH2OH) + CO2 =>
5(CH2)4(COOH)2 + 3 H2 = 4(HOCH2(CH2)4CH2OH) + 6 CO2
I2 + NaBH4 + C8H11N = C8H14NB + NaI + H2 =>
I2 + 2 NaBH4 + 2 C8H11N = 2 C8H14NB + 2 NaI + H2
C16H34 + O2 = CO2 + H2O =>
2 C16H34 + 49 O2 = 32 CO2 + 34 H2O
AlSO3 = Al(SO3) =>
AlSO3 = Al(SO3)
(CH2)4(COOH)2 + H2 = (HOCH2(CH2)4CH2OH) + CO2 =>
5(CH2)4(COOH)2 + 3 H2 = 4(HOCH2(CH2)4CH2OH) + 6 CO2
HAuCl4 + Na3C6H5O7 = Na2C6H6O7 + AuCl3 + NaCl =>
HAuCl4 + Na3C6H5O7 = Na2C6H6O7 + AuCl3 + NaCl
KY + KYO3 + H2SO4 = Y2 + K2SO4 + H2O =>
5 KY + KYO3 + 3 H2SO4 = 3 Y2 + 3 K2SO4 + 3 H2O
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 02/22/24
Equations balanced on 03/23/23
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